p^2=1p+110

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Solution for p^2=1p+110 equation:


Simplifying
p2 = 1p + 110

Reorder the terms:
p2 = 110 + 1p

Solving
p2 = 110 + 1p

Solving for variable 'p'.

Reorder the terms:
-110 + -1p + p2 = 110 + 1p + -110 + -1p

Reorder the terms:
-110 + -1p + p2 = 110 + -110 + 1p + -1p

Combine like terms: 110 + -110 = 0
-110 + -1p + p2 = 0 + 1p + -1p
-110 + -1p + p2 = 1p + -1p

Combine like terms: 1p + -1p = 0
-110 + -1p + p2 = 0

Factor a trinomial.
(-10 + -1p)(11 + -1p) = 0

Subproblem 1

Set the factor '(-10 + -1p)' equal to zero and attempt to solve: Simplifying -10 + -1p = 0 Solving -10 + -1p = 0 Move all terms containing p to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1p = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1p = 0 + 10 -1p = 0 + 10 Combine like terms: 0 + 10 = 10 -1p = 10 Divide each side by '-1'. p = -10 Simplifying p = -10

Subproblem 2

Set the factor '(11 + -1p)' equal to zero and attempt to solve: Simplifying 11 + -1p = 0 Solving 11 + -1p = 0 Move all terms containing p to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + -1p = 0 + -11 Combine like terms: 11 + -11 = 0 0 + -1p = 0 + -11 -1p = 0 + -11 Combine like terms: 0 + -11 = -11 -1p = -11 Divide each side by '-1'. p = 11 Simplifying p = 11

Solution

p = {-10, 11}

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